July 8, 1993: Bonilla's Homer Gives Mets Split
|Date: July 8, 1993|
|Mets starter: Eric Hillman|
|Winning pitcher: Jeff Innis|
|Key player(s): Bobby Bonilla, Joe Orsulak|
|Key play: Bonilla's home run in 10th|
After losing the first game of a doubleheader, the Mets faced the Dodgers in Game 2. The teams went into extra innings in the nightcap. Bobby Bonilla hit a three-run homer in the bottom of the tenth for a 6-3 Mets win and a split of the twinbill.
In the first inning, the Mets got off to a two-run lead against Los Angeles starter Tom Candiotti. Joe Orsulak hit a one-out double and came home on a triple by Jeromy Burnitz. Bonilla reached on an error by Dodger second baseman Mike Sharperson on which Burnitz scored. The Mets scored again in the third on Bonilla's sacrifice fly to bring home Orsulak and stretch the lead to 3-0.
In the sixth inning, Sharperson singled for only the second Los Angeles hit off Mets' starter Eric Hillman. After advancing to third base on two ground outs, Sharperson scored on Mitch Webster's triple. Hillman then balked to allow Webster to score. The Dodgers tied the game when Sharpeson doubled to score Eric Davis with two out in the seventh.
In the top of the ninth inning, the Dodgers had two runners on base with two out. For the Mets, Jeff Innis came in to relieve Pete Schourek. Innis struck out pinch-hitter Henry Rodriguez to end the inning and kept Los Angeles scoreless in the top of the tenth.
Orsulak started the bottom of the tenth with a double off the Dodgers' Rod Nichols. Burnitz was walked intentionally and Bonilla came to bat. Bobby homered off Nichols to give the Mets a three-run victory and a split of the doubleheader.