August 12, 1983: Terrell Shuts Out Cubs
|Date: August 12, 1983|
|Mets starter: Walt Terrell|
|Winning pitcher: Walt Terrell|
|Key player(s): Walt Terrell, Mookie Wilson, Danny Heep|
|Key play: Wilson's single in 5th, Heep's home run in 6th|
The Mets began a three-game series with the Cubs at Shea Stadium on a Friday night. Walt Terrell took the mound just six days after beating Chicago with his pitching and two home runs. Terrell continued to haunt the Cubs with a four-hit shutout in a 2-0 Mets win.
Like the previous game at Wrigley, Terrell was opposed by Chicago's Ferguson Jenkins. Walt and Fergie each started out with four scoreless innings. Terrell allowed only a single to the Cubs' Keith Moreland while Jenkins allowed three Met singles. Walt then retired Chicago in the top of the fifth with Moreland getting another single.
In the bottom of the fifth, Jenkins walked Ron Hodges with one out. Hodges moved to second base on Terrell's sacrifice bunt and came home on a single by Mookie Wilson. After Walt shut down the Cubs on one hit in the top of the sixth, Danny Heep homered off Jenkins in the bottom of the inning. Terrell then retired the Cubs in the seventh, yielding only a double to Bill Buckner.
In the eighth inning, Terrell walked Moreland to lead off. He then struck out Jody Davis and got Larry Bowa to fly out to center fielder Wilson. Walt got pinch-hitter Jay Johnstone on strikes to end the inning. The Mets then failed to score against Chicago's Craig Lefferts in the bottom half.
Terrell retired the Cubs 1-2-3 in the top of the ninth to end the game. The Mets had a victory on Walt's first career shutout. It was Terrell's second win in as many games against the Chicago team.